Counting Values in 2D Array

A 2D array stores values in rows and columns.
The following array stores prices of meals for 5 days.
It has 3 rows and 5 columns.

   double[][] prices ={
                                {4.00 ,  4.50 , 5.95 ,   0  ,  1.95} ,
                                {  0   , 12.50, 3.50 ,   0  ,     0  },
                                {5.00 , 19.95,29.50,   0  , 10.00}
                             };

Apparently this person was not hungry on Thursday.
Use nested loops to count the number of prices that equal zero.              

Solution

int count = 0;

for(int r = 0; r < 3; r = r+1)
{
    for(int c = 0; c < 5; c = c+1)
    {
        if(prices[r][c] == 0)
        {  count = count + 1; } 
    }
}

output("Number of 0 prices = " + count );