Famous Circuits
There are 6 standard logic gates :
or
nor
xor
not
and
nand
Here are the truth tables for these gates - 0 means false, 1 means true:
|
|
|
|||||||||||||||||||||||||||||||||||||||||||||
|
|
|
The and , or , not , xor gates
represents standard logic concepts.
They can be built into microprocessors
using transistors and other bipolar devices.
The nand , nor gates are not really "standard"
logic - people don't think this way.
But these are very simple to construct, makeing cheap
and efficient circuits.
You may have seen advertisements for memory
devices, saying they use
"nand" logic. That means the cirucuits
are built from nand gates.
This is very efficient and saves money.
== NAND Gates ==
It
is a fact that any circuit can be constructed using only nand
gates.
To prove this fact, we show how or , and , not , xor can be constructed
from nand's. Here are the famous circuits that prove this:
A or B A and B
not A A xor B
The xor gate has been constructed from and, or, not. Since
those could
in turn be constructed from nand gates, it is possible
to construct xor
from nand gates. But that would be quite
complex.
== DeMorgan's Laws ==
The or circuit above is based on DeMorgan's law, which states:
not(A
or B) = (not A) and (not B)
By applying not to both sides, we get:
A
or B = not( not A and not B
) = (not A) nand (not B)
Since A nand A = not A, this is equivalent to the circuit above.
DeMorgan's other law says something similar for or (and nor):
__
__ __
__
not(A
and B) = A or B
= A or B
__
__ __
__
A
and B = not( A or B )
= A nor B
That means the and gate can be consructed using
nor gates,
like this:
A
and B
== Equivalent Expressions ==
Two Boolean Expressions are equivalent if they always produce
the
same result, for any values of the variables.
Decide whether each of the following equivalences are
CORRECT.
Recall that AB = A and B , A+B = A or B.
A nor A = not A right
A nand B = (not A) and (not B) wrong
(not A) or (not B) = not(A and
B) right
_____
__ __
A + B =
A B right
_____
(A
+ B ) ( A B ) = A ⊕ B = A xor B right
__
(A+B)B
= A + B wrong
__
A
(A + B) = B right
== Equivalent Circuits ==
Two circuits are equivalent if they have the same truth-table
-
that means they produce the same output from the same input.
There are 4 circuits below. By "tracing" each circuit for various
values of A and B (switches),
decide which two are equivalent.
|
Answer: Top left circuit Top right circuit |
== Changing Circuits to Formulas ==
If you have a drawing of a circuit (like those above)
you can write a
boolean expression that means the same thing.
__
Top
left : AB + B Top
right : not(not A or B)
__
__
Bottom
left: A . B Bottom
right : A + B
== Truth Tables ==
Another way to represent a circuit or Boolean expression is
in a truth
table. For all possible value of the inputs, write
a line showing
the corresponding output. Here are the truth
tables for the expressions
and formulas above.
|
|
||||||||||||||||||||||||||||||
|
|
== More NAND Gates ==
It is possible to create a circuit using only nands that is
equivalent to xor.
The circuit above will be very complex,
so a simpler one is desirable.
For each of the following, decide
whether it
is equivalent to xor.
It might help to start by looking at the truth
table for xor.
A |
B |
A xor B |
0 |
0 |
0 |
0 |
1 |
1 |
1 |
0 |
1 |
1 |
1 |
0 |
no,
not equivalent to xor no,
it's equivalent to nor
yes,
this is equivalent to xor YES,
this is
equivalent to xor