Yes. New lines are inserted into the program to show this:
In the revised program, the print() method is used
first with one array, and then with the other array.
This is possible because the parameter x of the method
refers to the current array, 
whichever one is used in the method "call."
import java.io.*;
class ArrayOps
{
  void print( int[] x )
  {
    for ( int index=0; index < x.length; index++ )
      System.out.print( x[index] + " " );
    System.out.println();
  }
}
class ArrayDemo
{
  public static void main ( String[] args ) 
  {
    ArrayOps operate = new ArrayOps();
    int[] ar1 =  { -20, 19, 1, 5, -1, 27, 19, 5 } ;
    int[] ar2 =  { 2, 4, 1, 2, 6, 3, 6, 9 } ;
    System.out.print  ("\nThe array is: " );
    operate.print( ar1 );  // method call with the 1st array
    System.out.print  ("\nThe second array is: " );
    operate.print( ar2 );   // method call with the 2nd array
  }
}      
The program will print the following:
C:\>java ArrayDemo The array is:-20 19 1 5 -1 27 19 5 The second array is: 2 4 1 2 6 3 6 9