A good answer might be:

No. The reference in source will be copied into target, but this will have no effect on the actual arrays because source and target are formal parameters of copy(). The variables s and t of the main program will not be changed, nor will any array element be changed.

End of the Chapter

That about wraps it up for this chapter. You may wish to review the following. Click on a subject that interests you to go to where it was discussed.

Call by value.
Picture of an array used as a parameter.
Step-by-step description of call by value with an array.
ZeroAll() method.
ArrayCopy() method.

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