Since this is an exception, the program can handle it (with the right code.)
try{} and catch{} To catch an exception:
try{} block.catch{} block.Here is the example program with code added to do this:
import java.lang.* ;
import java.io.* ;
public class Square
{
public static void main ( String[] a ) throws IOException
{
BufferedReader stdin =
new BufferedReader ( new InputStreamReader( System.in ) );
String inData;
int num ;
System.out.println("Enter an integer:");
inData = stdin.readLine();
try
{
num = Integer.parseInt( inData );
System.out.println("The square of " + inData + " is " + num*num );
}
catch (NumberFormatException ex )
{
System.out.println("You entered bad data." );
System.out.println("Run the program again." );
}
System.out.println("Good-by" );
}
}
If a statement inside the try{} block throws a
NumberFormatException,
the catch{} block immediately starts running.
The remaining statements in the try{} block are skipped.
The reference variable ex refers to
the Exception object.
(However, this example does nothing with it.)
After the catch{} block is executed,
execution continues
with the statement that follows the catch{} block.
(Execution does not return to the try{} block.)